1-5/x-1=-10/x^2-1

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Solution for 1-5/x-1=-10/x^2-1 equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

1-(5/x)-1 = -10/(x^2)-1 // + -10/(x^2)-1

1-(5/x)-(-10/(x^2))-1+1 = 0

10*x^-2-5*x^-1-1+1+1 = 0

10*x^-2-5*x^-1+1 = 0

t_1 = x^-1

10*t_1^2-5*t_1^1+1 = 0

10*t_1^2-5*t_1+1 = 0

DELTA = (-5)^2-(1*4*10)

DELTA = -15

DELTA < 0

x belongs to the empty set

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